An inductance of negligible resistance, whose reactance is 120 Ω at 200 Hz is connected to a 240 V, 60 Hz Power line. The current in the inductor is (a) 6.66 A (b) 6.60 A (c) 5.45 A (d) 54.5 A

Answer: (a). XL = 2π fL ∝ f, so at 60 Hz: XL = 120 × 60/200 = 36 Ω. I = V/XL = 240/36 = 6.67 A So the answer is (a) 6.66 A.

An inductance of negligible resistance, whose reactance is 120 Ω at… | MHT CET 2026 (13 May, Shift 2)

Q5MHT CET 2026 · 13 MAY · SHIFT 2Easy

Pure R, L and C Circuits

An inductance of negligible resistance, whose reactance is $120\ \Omega$ at $200$ Hz is connected to a $240$ V, $60$ Hz Power line. The current in the inductor is

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Answer: (a)

$X_L = 2\pi fL \propto f$ , so at 60 Hz: $X_L = 120 \times \frac{60}{200} = 36\ \Omega$ .
$I = \frac{V}{X_L} = \frac{240}{36} = 6.67$ A
So the answer is (a) $6.66$ A.

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Pure R, L and C Circuits question from MHT CET 2026 (13 May, Shift 2)

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