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NEET 2016 (Phase 1) · Power, Power Factor & Wattless Current

Power, Power Factor & Wattless Current question from NEET 2016 (Phase 1)

Q67NEET 2016 · PHASE 1Medium

Power, Power Factor & Wattless Current

An inductor 20 mH, a capacitor 50 μF\mu F and a resistor 40 Ω\Omega are connected in series across a source of emf V = 10 sin 340t. The power loss in A.C. circuit is

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Answer: (c)

  1. ω=340\omega = 340 rad/s: XL=340×0.02=6.8 ΩX_L = 340 \times 0.02 = 6.8\ \Omega, XC=1340×50×10−6=58.8 ΩX_C = \frac{1}{340 \times 50 \times 10^{-6}} = 58.8\ \Omega.
  2. Z2=402+(58.8−6.8)2=1600+2704=4304 Ω2Z^2 = 40^2 + (58.8 - 6.8)^2 = 1600 + 2704 = 4304\ \Omega^2.
  3. Vrms2=1022=50 V2V_{rms}^2 = \frac{10^2}{2} = 50\text{ V}^2.
  4. P=Vrms2RZ2=50×404304≈0.46 WP = \frac{V_{rms}^2R}{Z^2} = \frac{50 \times 40}{4304} \approx 0.46\text{ W}, closest option 0.51 W.
  5. So the answer is (c) 0.51 W.
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