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MHT CET 2026 (13 Apr, Shift 2) · Resonance, Bandwidth & Q Factor

Resonance, Bandwidth & Q Factor question from MHT CET 2026 (13 Apr, Shift 2)

Q12MHT CET 2026 · 13 APR · SHIFT 2Easy

Resonance, Bandwidth & Q Factor

An inductor of $0.5$ mH, a capacitor of $20\ \mu$ F and resistance $20\ \Omega$ are connected in series with a $220$ V ac source. If the current is in phase with the emf, the amplitude of current of the circuit is $[x]^{1/2}$ A. The value of $x$ is

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Answer: (c)

In phase means resonance, so $Z = R = 20\ \Omega$ .
Peak emf $E_0 = 220\sqrt{2}\text{ V}$ (220 V is the rms value).
$I_0 = \dfrac{E_0}{R} = \dfrac{220\sqrt{2}}{20} = 11\sqrt{2} = \sqrt{242}\text{ A}$
So the answer is (c) 242.

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