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MHT CET 2025 (5 May, Shift 2) · Series LCR Circuit

Series LCR Circuit question from MHT CET 2025 (5 May, Shift 2)

Q19MHT CET 2025 · 5 MAY · SHIFT 2Medium

Series LCR Circuit

An inductor of $\left(\frac{100}{\pi}\right)\text{ mH}$ , capacitor of capacitance $\left(\frac{10^{-3}}{2\pi}\right)\text{ F}$ and resistance of $10\ \Omega$ are connected in series with an AC voltage source of $110\text{ V},\ 50\text{ Hz}$ supply. The tangent of the phase angle ' $\phi$ ' between voltage and current is

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Answer: (d)

$X_L = 2\pi fL = 2\pi \times 50 \times \dfrac{0.1}{\pi} = 10\ \Omega$
$X_C = \dfrac{1}{2\pi fC} = \dfrac{1}{2\pi \times 50 \times \frac{10^{-3}}{2\pi}} = 20\ \Omega$
$\tan\phi = \dfrac{|X_C - X_L|}{R} = \dfrac{10}{10} = 1$
So the answer is (d) 1.

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