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JEE Main 2026 (6 Apr, Shift 1) · Combination of Inductors, LR & LC Circuits

Combination of Inductors, LR & LC Circuits question from JEE Main 2026 (6 Apr, Shift 1)

Q9JEE Main 2026 · 6 APR · SHIFT 1Medium

Combination of Inductors, LR & LC Circuits

An inductor of inductance 10 mH having resistance of 100 Ω100\,\Omega is connected to battery of E.M.F. 1.0 V through a switch as shown in the figure below. After switch is closed, the ratio of instantaneous voltages across the inductor when the current passing through it is 2 mA and 4 mA is ______.

Figure

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Answer: (a)

  1. Voltage across the inductor: VL=E−IRV_L = E - IR
  2. I=2 mAI = 2\text{ mA}: VL=1−0.2=0.8 VV_L = 1 - 0.2 = 0.8\text{ V}; I=4 mAI = 4\text{ mA}: VL=1−0.4=0.6 VV_L = 1 - 0.4 = 0.6\text{ V}
  3. Ratio =0.80.6=43= \frac{0.8}{0.6} = \frac{4}{3}
  4. So the answer is (a).
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