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MHT CET 2026 (16 Apr, Shift 2) · Resonance, Bandwidth & Q Factor

Resonance, Bandwidth & Q Factor question from MHT CET 2026 (16 Apr, Shift 2)

Q5MHT CET 2026 · 16 APR · SHIFT 2Easy

Resonance, Bandwidth & Q Factor

An inductor of inductance $2\ \mu$ H is connected in series with a resistance, a variable capacitor and an a.c. source of 10 kHz. The value of capacitance for which maximum current is drawn in to the circuit is $\frac{1}{x}$ F, where the value of x is (Take $\pi^2 = 10$ )

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Answer: (a)

Maximum current at resonance: $C = \dfrac{1}{4\pi^2 f^2 L}$ .
$C = \dfrac{1}{4 \times 10 \times (10^4)^2 \times 2\times10^{-6}} = \dfrac{1}{8000}\text{ F}$
So $x = 8000$ , answer (a).

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