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JEE Main 2021 (18 Mar, Shift 2) · Electric Charge & Coulomb's Law

Electric Charge & Coulomb's Law question from JEE Main 2021 (18 Mar, Shift 2)

Q59JEE Main 2021 · 18 MAR · SHIFT 2Medium

Electric Charge & Coulomb's Law

An infinite number of point charges, each carrying 1 μ\muC charge, are placed along the y-axis at y = 1 m, 2 m, 4 m, 8 m ...............

The total force on a 1C point charge, placed at the origin, is x ×\times 103 N.

The value of x, to the nearest integer, is __________. [Take 14πε0=9×109\frac{1}{4\pi\varepsilon_0} = 9 \times 10^{9} Nm2/C2]

Numerical answer type. Work it out, then open the answer.

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Answer: 12

  1. All forces on the charge at the origin act along the same line (along −y-y, repulsion).
  2. F=kq Q(112+122+142+… )F = kq\,Q\left(\dfrac{1}{1^2} + \dfrac{1}{2^2} + \dfrac{1}{4^2} + \dots\right), a GP with ratio 14\tfrac{1}{4}, sum =11−1/4=43= \dfrac{1}{1 - 1/4} = \dfrac{4}{3}.
  3. F=9×109×10−6×1×43=12×103 NF = 9 \times 10^9 \times 10^{-6} \times 1 \times \dfrac{4}{3} = 12 \times 10^3\text{ N}
  4. So x=12x = 12.
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