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MHT CET 2025 (26 Apr, Shift 1) · Magnetic Field of Straight Wires

Magnetic Field of Straight Wires question from MHT CET 2025 (26 Apr, Shift 1)

Q20MHT CET 2025 · 26 APR · SHIFT 1Medium

Magnetic Field of Straight Wires

An infinitely long straight conductor carrying current ' II ' is bent into a shape as shown in figure. The radius of the circular loop is ' rr '. The magnetic induction at the centre of the loop at point ' O ' is ( μ0=\mu_0 = permeability of free space)

Figure

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Answer: (d)

  1. Infinite straight wire at distance rr: μ0I2πr\frac{\mu_0 I}{2\pi r}, out of the page (current right, O above).
  2. Circular loop (clockwise): μ0I2r\frac{\mu_0 I}{2r}, into the page.
  3. B=μ0I2r−μ0I2πr=μ0I2πr(π−1)B = \frac{\mu_0 I}{2r} - \frac{\mu_0 I}{2\pi r} = \frac{\mu_0 I}{2\pi r}(\pi - 1)
  4. So the answer is (d).
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