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MHT CET 2024 (11 May, Shift 1) · Refraction, Glass Slab & Apparent Depth

Refraction, Glass Slab & Apparent Depth question from MHT CET 2024 (11 May, Shift 1)

Q27MHT CET 2024 · 11 MAY · SHIFT 1Medium

Refraction, Glass Slab & Apparent Depth

An ink mark is made on a piece of paper. A glass slab of thickness ' $t$ ' is placed on it. The ink mark appears to be raised up through a distance ' $x$ ' when viewed at nearly normal incidence. If the refractive index of material of glass slab is ' $\mu$ ' then thickness of glass slab ' $t$ ' is given by

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Answer: (b)

Normal shift: $x = t - \dfrac{t}{\mu} = t\left(1 - \dfrac{1}{\mu}\right) = t\,\dfrac{\mu - 1}{\mu}$ .
$t = \dfrac{\mu x}{\mu - 1}$ .
So the answer is (b).

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