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MHT CET 2026 (11 Apr, Shift 2) · Degrees of Freedom & Internal Energy

Degrees of Freedom & Internal Energy question from MHT CET 2026 (11 Apr, Shift 2)

Q5MHT CET 2026 · 11 APR · SHIFT 2Medium

Degrees of Freedom & Internal Energy

An insulated container contains a monoatomic gas of molar mass 'm'. The container is moving with velocity 'V'. If it is stopped suddenly, the change in temperature of the gas is (R-gas constant)

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Answer: (c)

  1. KE lost per mole goes into internal energy: 12mv2=CvΔT\frac{1}{2}mv^2 = C_v\Delta T.
  2. Monoatomic: Cv=32RC_v = \frac{3}{2}R.
  3. ΔT=mv22⋅32R=mv23R\Delta T = \frac{mv^2}{2\cdot\frac{3}{2}R} = \frac{mv^2}{3R}
  4. So the answer is (c) mv23R\frac{mv^2}{3R}.
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