An insulated cylinder of volume 60 cm³ is filled with a gas at 27 and 2 atmospheric pressure. Then the gas is compressed making the final volume as 20 cm³ while allowing the temperature to rise to 77. The final pressure is ______ atmospheric pressure. Numerical answer type. Work it out, then open the answer.

Answer: 7. Same gas: (P₁V₁)/(T₁) = (P₂V₂)/(T₂). T₁ = 300 K, T₂ = 350 K. P₂ = P₁(V₁)/(V₂)·(T₂)/(T₁) = 2 × 60/20 × (350)/(300) = 7 atm. Final pressure = 7 atm.

An insulated cylinder of volume 60 cm³ is filled with a gas at 27 and… | JEE Main 2026 (22 Jan, Shift 2)

Q10JEE Main 2026 · 22 JAN · SHIFT 2Medium

Gas Laws & Ideal Gas Equation

An insulated cylinder of volume $60\text{ cm}^{3}$ is filled with a gas at $27^\circ\text{C}$ and 2 atmospheric pressure. Then the gas is compressed making the final volume as $20\text{ cm}^{3}$ while allowing the temperature to rise to $77^\circ\text{C}$ . The final pressure is ______ atmospheric pressure.

Numerical answer type. Work it out, then open the answer.

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Answer: 7

Same gas: $\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}$ .
$T_1 = 300\text{ K}$ , $T_2 = 350\text{ K}$ .
$P_2 = P_1\frac{V_1}{V_2}\cdot\frac{T_2}{T_1} = 2 \times \frac{60}{20} \times \frac{350}{300} = 7$ atm.
Final pressure = 7 atm.

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