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MHT CET 2026 (13 Apr, Shift 1) · Magnetisation: B, H, M, χ & μ

Magnetisation: B, H, M, χ & μ question from MHT CET 2026 (13 Apr, Shift 1)

Q4MHT CET 2026 · 13 APR · SHIFT 1Easy

Magnetisation: B, H, M, χ & μ

An iron rod is placed parallel to magnetic field intensity 2000 A/m. The magnetic flux through rod is 6×10−46 \times 10^{-4} wb and its cross sectional area is 3 cm2{}^{2}. The magnetic permeability of the rod in wb/A-m is

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Answer: (c)

  1. B=ΦA=6×10−43×10−4=2 TB = \dfrac{\Phi}{A} = \dfrac{6\times10^{-4}}{3\times10^{-4}} = 2\text{ T}
  2. μ=BH=22000=10−3 Wb/A-m\mu = \dfrac{B}{H} = \dfrac{2}{2000} = 10^{-3}\text{ Wb/A-m}
  3. So the answer is (c).
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