Physics Circle home Student Login

Home›Chapters›Thermometry, Thermal Expansion and Calorimetry PYQs›Thermometry & Thermal Expansion›Question 7

MHT CET 2026 (15 May, Shift 1) · Thermometry & Thermal Expansion

Thermometry & Thermal Expansion question from MHT CET 2026 (15 May, Shift 1)

Q7MHT CET 2026 · 15 MAY · SHIFT 1Medium

Thermometry & Thermal Expansion

An iron tyre is to be fitted on to a wooden wheel 1.01.0 m in diameter. The diameter of the tyre is 66 mm smaller than that of the wheel. The tyre should be heated so that its temperature increases by a minimum of

(coefficient of volume expansion of iron = 3.6×10−5/∘3.6 \times 10^{-5}/^\circC)

Show answer and solution

Answer: (c)

  1. α=γ3=1.2×10−5/∘\alpha=\frac{\gamma}{3}=1.2\times10^{-5}/^\circC; the diameter must grow by 66 mm.
  2. ΔT=Δdd α=6×10−31.0×1.2×10−5=500∘\Delta T=\frac{\Delta d}{d\,\alpha}=\frac{6\times10^{-3}}{1.0\times1.2\times10^{-5}}=500^\circC
  3. So the answer is (c) 500∘500^\circC.
Report a mistake

More questions on Thermometry & Thermal Expansion