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JEE Main 2022 (28 Jul, Shift 2) · Junction Transistor

Junction Transistor question from JEE Main 2022 (28 Jul, Shift 2)

Q56JEE Main 2022 · 28 JUL · SHIFT 2Medium

Junction Transistor

An n.p.n transistor with current gain $\beta = 100$ in common emitter configuration is shown in figure. The output voltage of the amplifier will be

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Answer: (b)

Voltage gain of CE amplifier: $A_v = \beta \dfrac{R_L}{R_{in}}$
$A_v = 100 \times \dfrac{10\ \text{k}\Omega}{1\ \text{k}\Omega} = 1000$
$V_{out} = A_v V_{in} = 1000 \times 1\ \text{mV} = 1\ \text{V}$
So the answer is (b) 1.0 V.

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