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JEE Main 2022 (28 Jul, Shift 1) · Motion Under Gravity

Motion Under Gravity question from JEE Main 2022 (28 Jul, Shift 1)

Q20JEE Main 2022 · 28 JUL · SHIFT 1Easy

Motion Under Gravity

An NCC parade is going at a uniform speed of 9 km/h9\text{ km/h} under a mango tree on which a monkey is sitting at a height of 19.6 m19.6\text{ m}. At any particular instant, the monkey drops a mango. A cadet will receive the mango whose distance from the tree at time of drop is: (Given g=9.8 m/s2g = 9.8\text{ m/s}^2)

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Answer: (a)

  1. Time of fall: t=2h/g=2×19.6/9.8=2t = \sqrt{2h/g} = \sqrt{2 \times 19.6/9.8} = 2 s
  2. Parade speed: 99 km/h =9×518=2.5= 9 \times \frac{5}{18} = 2.5 m/s
  3. The cadet must be d=2.5×2=5d = 2.5 \times 2 = 5 m from the tree at the instant of drop.
  4. So the answer is (a) 5 m.
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