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MHT CET 2021 (23 Sep, Shift 2) · Energy in SHM

Energy in SHM question from MHT CET 2021 (23 Sep, Shift 2)

Q62MHT CET 2021 · 23 SEP · SHIFT 2Medium

Energy in SHM

An object executes SHM along xx-axis with amplitude 0.06 m0.06\text{ m}. At certain distance 'xx' metre from mean position, it has kinetic energy 10 J10\text{ J} and potential energy 8 J8\text{ J}. the distance 'xx' will be

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Answer: (c)

  1. E=10+8=18E = 10 + 8 = 18 J
  2. x2A2=PEE=818=49⇒x=23A\frac{x^2}{A^2} = \frac{PE}{E} = \frac{8}{18} = \frac{4}{9} \Rightarrow x = \frac{2}{3}A
  3. x=23×0.06=0.04x = \frac{2}{3} \times 0.06 = 0.04 m
  4. So the answer is (c) 0.04 m.
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