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JEE Main 2023 (30 Jan, Shift 2) · Escape Velocity

Escape Velocity question from JEE Main 2023 (30 Jan, Shift 2)

Q36JEE Main 2023 · 30 JAN · SHIFT 2Medium

Escape Velocity

An object is allowed to fall from a height RR above the earth, where RR is the radius of earth. Its velocity when it strikes the earth's surface, ignoring air resistance, will be

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Answer: (b)

  1. Released at 2R2R from the centre: 12v2=GM(1R−12R)=GM2R\frac{1}{2}v^2 = GM\left(\frac{1}{R} - \frac{1}{2R}\right) = \frac{GM}{2R}.
  2. v2=GMR=gRv^2 = \frac{GM}{R} = gR.
  3. So the answer is (b) gR\sqrt{gR}.
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