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JEE Main 2019 (11 Jan, Shift 1) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from JEE Main 2019 (11 Jan, Shift 1)

Q93JEE Main 2019 · 11 JAN · SHIFT 1Medium

Spherical Surfaces & Thin Lenses

An object is at a distance of 20 m from a convex lens of focal length 0.3 m. The lens forms an image of the object. If the object moves away from the lens at a speed of 5 m/s, the speed and direction of the image will be:

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Answer: (a)

  1. 1v=10.3−120=3.283⇒v≈0.3046\frac{1}{v} = \frac{1}{0.3} - \frac{1}{20} = 3.283 \Rightarrow v \approx 0.3046 m
  2. Image speed: ∣vi∣=v2u2∣vo∣=(0.304620)2×5|v_i| = \frac{v^2}{u^2}|v_o| = \left(\frac{0.3046}{20}\right)^2 \times 5
  3. ∣vi∣≈1.16×10−3|v_i| \approx 1.16 \times 10^{-3} m/s
  4. As the object moves away the image moves towards the focus, i.e. towards the lens. So the answer is (a).
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