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JEE Main 2017 (8 Apr, Shift 1) · Collisions

Collisions question from JEE Main 2017 (8 Apr, Shift 1)

Q8JEE Main 2017 · 8 APR · SHIFT 1Medium

Collisions

An object is dropped from a height h from the ground. Every time it hits the ground it loses 50% of its kinetic energy. The total distance covered as t $\to \infty$ is:

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Answer: (a)

Each bounce keeps half the KE, so each rebound height is half the previous: $h, \frac{h}{2}, \frac{h}{4}, \dots$
Distance $= h + 2\left(\frac{h}{2} + \frac{h}{4} + \dots\right) = h + 2h$
$= 3h$
So the answer is (a) 3h.

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