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JEE Main 2021 (17 Mar, Shift 2) · Bulk Modulus & Compressibility

Bulk Modulus & Compressibility question from JEE Main 2021 (17 Mar, Shift 2)

Q12JEE Main 2021 · 17 MAR · SHIFT 2Medium

Bulk Modulus & Compressibility

An object is located at 2 km beneath the surface of the water. If the fractional compression ΔVV\frac{\Delta V}{V} is 1.36%, the ratio of hydraulic stress to the corresponding hydraulic strain will be ____________. [Given: density of water is 1000 kgm−3 and g = 9.8 ms−2]

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Answer: (b)

  1. Hydraulic stress at depth: P=ρgh=1000×9.8×2000=1.96×107 PaP = \rho g h = 1000\times9.8\times2000 = 1.96\times10^{7}\ \text{Pa}.
  2. Stress/strain =B=PΔV/V=1.96×1070.0136= B = \frac{P}{\Delta V/V} = \frac{1.96\times10^{7}}{0.0136}
  3. B≈1.44×109 N m−2B \approx 1.44\times10^{9}\ \text{N m}^{-2}
  4. So the answer is (b).
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