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MHT CET 2021 (22 Sep, Shift 2) · Spherical Surfaces & Thin Lenses

Spherical Surfaces & Thin Lenses question from MHT CET 2021 (22 Sep, Shift 2)

Q80MHT CET 2021 · 22 SEP · SHIFT 2Medium

Spherical Surfaces & Thin Lenses

An object is located on a wall, its image of equal size is to be obtained on a parallel wall with the help of a convex lens. The lens is placed at a distance 'dd' in front of the second wall. The required focal length of the lens is

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Answer: (d)

  1. Equal size real image means ∣u∣=v=2f|u| = v = 2f.
  2. Image distance is the lens-to-second-wall distance: v=d=2fv = d = 2f.
  3. f=d2f = \frac{d}{2}
  4. So the answer is (d) only d2\frac{d}{2}.
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