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JEE Main 2024 (27 Jan, Shift 2) · Momentum & Radiation Pressure

Momentum & Radiation Pressure question from JEE Main 2024 (27 Jan, Shift 2)

Q5JEE Main 2024 · 27 JAN · SHIFT 2Medium

Momentum & Radiation Pressure

An object is placed in a medium of refractive index 3. An electromagnetic wave of intensity 6×108 W/m26 \times 10^{8}\text{ W/m}^2 falls normally on the object and it is absorbed completely. The radiation pressure on the object would be (speed of light in free space =3×108 m/s= 3 \times 10^{8}\text{ m/s}):

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Answer: (a)

  1. In a medium the wave speed is v=c/n=108 m/sv = c/n = 10^8\ \text{m/s}
  2. For complete absorption, pressure =Iv=nIc= \dfrac{I}{v} = \dfrac{nI}{c}
  3. P=3×6×1083×108=6 N m−2P = \dfrac{3 \times 6 \times 10^8}{3 \times 10^8} = 6\ \text{N m}^{-2}
  4. So the answer is (a).
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