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NEET 2020 (Phase 2) · Reflection & Mirrors

Reflection & Mirrors question from NEET 2020 (Phase 2)

Q37NEET 2020 · PHASE 2Easy

Reflection & Mirrors

An object is placed on the principal axis of a concave mirror at a distance of $1.5f$ ( $f$ is the focal length). The image will be at,

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Answer: (b)

Concave mirror: $f \to -f$ , $u = -1.5f$ .
$\frac{1}{v} = \frac{1}{f} - \frac{1}{u} = -\frac{1}{f} + \frac{1}{1.5f} = -\frac{1}{3f}$
$v = -3f$ (real image in front of the mirror).
So the answer is (b) $-3f$ .

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