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JEE Main 2022 (25 Jul, Shift 2) · Acceleration Due to Gravity

Acceleration Due to Gravity question from JEE Main 2022 (25 Jul, Shift 2)

Q80JEE Main 2022 · 25 JUL · SHIFT 2Medium

Acceleration Due to Gravity

An object is taken to a height above the surface of earth at a distance 54\frac{5}{4} R from the centre of the earth. Where radius of earth, R = 6400 km. The percentage decrease in the weight of the object will be:

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Answer: (a)

  1. g∝1r2g \propto \frac{1}{r^2}, with r=54Rr = \frac{5}{4}R
  2. g′=g(45)2=1625g=0.64gg' = g\left(\frac{4}{5}\right)^2 = \frac{16}{25}g = 0.64g
  3. Decrease in weight =(1−0.64)×100%=36%= (1-0.64)\times 100\% = 36\%
  4. So the answer is (a) 36%.
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