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JEE Main 2022 (29 Jul, Shift 2) · Gravitational Potential & Energy

Gravitational Potential & Energy question from JEE Main 2022 (29 Jul, Shift 2)

Q15JEE Main 2022 · 29 JUL · SHIFT 2Medium

Gravitational Potential & Energy

An object of mass 1 kg1\text{ kg} is taken to a height from the surface of earth which is equal to three times the radius of earth. The gain in potential energy of the object will be [If, g=10 m s−2g = 10\text{ m s}^{-2} and radius of earth =6400 km= 6400\text{ km} ]

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Answer: (a)

  1. ΔU=mgh1+h/R\Delta U = \frac{mgh}{1+h/R} with h=3Rh = 3R gives ΔU=34mgR\Delta U = \frac{3}{4}mgR
  2. ΔU=34×1×10×6.4×106\Delta U = \frac{3}{4} \times 1 \times 10 \times 6.4\times10^{6} J
  3. ΔU=4.8×107\Delta U = 4.8\times10^{7} J
  4. So the answer is (a) 48 MJ.
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