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Acceleration Due to Gravity question from NEET 2024

Q37NEET 2024Medium

Acceleration Due to Gravity

An object of mass 100 kg100\text{ kg} falls from point AA to BB as shown in figure. The change in its weight, corrected to the nearest integer is (RER_E is the radius of the earth)

Figure

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Answer: (a)

  1. AA is at height 2Re2R_e and BB at height 2Re−Re2=1.5Re2R_e - \frac{R_e}{2} = 1.5R_e; gh=g(1+h/Re)2g_h = \frac{g}{(1 + h/R_e)^2}.
  2. gA=1032=1.11 m s−2g_A = \frac{10}{3^2} = 1.11\text{ m s}^{-2}, gB=10(2.5)2=1.60 m s−2g_B = \frac{10}{(2.5)^2} = 1.60\text{ m s}^{-2}
  3. ΔW=m(gB−gA)=100×0.49≈49 N\Delta W = m(g_B - g_A) = 100 \times 0.49 \approx 49\text{ N}
  4. So the answer is (a) 49 N49\text{ N}.
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