An object of mass 3 kg is at rest. Now a force of F = 6t2 i + 4t j is applied on the object then velocity of object at t = 3 sec. is (a) 18 i + 3 j (b) 18 i + 6 j (c) 3 i + 18 j (d) 18 i + 4 j

Answer: (b). a = F/m = 2t²i + 4/3tj v = ∫₀t a dt = 2/3t³i + 2/3t²j At t = 3 s: v = 18i + 6j. So the answer is (b).

An object of mass 3 kg is at rest. Now a force of F = 6t2 i + 4t j is… | NEET 2002 (AIPMT)

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Inertia, First & Second Laws

An object of mass 3 kg is at rest. Now a force of $\vec{F}$ = 6t2 $\hat{i}$ + 4t $\hat{j}$ is applied on the object then velocity of object at t = 3 sec. is

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Answer: (b)

$\vec{a} = \frac{\vec{F}}{m} = 2t^2\hat{i} + \frac{4}{3}t\hat{j}$
$\vec{v} = \int_0^t \vec{a}\,dt = \frac{2}{3}t^3\hat{i} + \frac{2}{3}t^2\hat{j}$
At $t = 3$ s: $\vec{v} = 18\hat{i} + 6\hat{j}$ . So the answer is (b).

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