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JEE Main 2020 (6 Sep, Shift 1) · Wire Combinations & Special Cases

Wire Combinations & Special Cases question from JEE Main 2020 (6 Sep, Shift 1)

Q23JEE Main 2020 · 6 SEP · SHIFT 1Medium

Wire Combinations & Special Cases

An object of mass m is suspended at the end of a massless wire of length L and area of crosssection A. Young modulus of the material of the wire is Y. If the mass is pulled down slightly its frequency of oscillation along the vertical direction is:

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Answer: (a)

The wire acts as a spring: $F = \frac{YA}{L}\Delta l$ , so $k = \frac{YA}{L}$
$f = \frac{1}{2\pi}\sqrt{\frac{k}{m}} = \frac{1}{2\pi}\sqrt{\frac{YA}{mL}}$
So the answer is (a).

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