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JEE Main 2025 (7 Apr, Shift 2) · Inertia, First & Second Laws

Inertia, First & Second Laws question from JEE Main 2025 (7 Apr, Shift 2)

Q7JEE Main 2025 · 7 APR · SHIFT 2Medium

Inertia, First & Second Laws

An object with mass 500 g moves along x-axis with speed v=4xv = 4\sqrt{x} m/s. The force acting on the object is:

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Answer: (b)

  1. a=vdvdx=4x×2x=8 m/s2a = v\frac{dv}{dx} = 4\sqrt{x} \times \frac{2}{\sqrt{x}} = 8\text{ m/s}^2
  2. F=ma=0.5×8=4 NF = ma = 0.5 \times 8 = 4\text{ N}
  3. So the answer is (b) 4 N.
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