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JEE Main 2022 (27 Jun, Shift 1) · Doppler Effect

Doppler Effect question from JEE Main 2022 (27 Jun, Shift 1)

Q38JEE Main 2022 · 27 JUN · SHIFT 1Easy

Doppler Effect

An observer moves towards a stationary source of sound with a velocity equal to one-fifth of the velocity of sound. The percentage change in the frequency will be:

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Answer: (a)

  1. Observer approaching: n′=nv+vovn' = n\frac{v + v_o}{v}.
  2. n′=n(1+15)=1.2nn' = n\left(1 + \frac{1}{5}\right) = 1.2n
  3. Change =20%= 20\%. So the answer is (a) 20%.
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