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MHT CET 2024 (3 May, Shift 2) · Doppler Effect

Doppler Effect question from MHT CET 2024 (3 May, Shift 2)

Q20MHT CET 2024 · 3 MAY · SHIFT 2Easy

Doppler Effect

An observer moves towards a stationary source of sound with a velocity of one-fifth of the velocity of sound. The percentage increase in the apparent frequency is

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Answer: (c)

Observer approaching: $n' = n\frac{v + v_o}{v}$ .
$n' = n\left(1 + \frac{1}{5}\right) = 1.2n$
Increase $= 20\%$ . So the answer is (c) $20\%$ .

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