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MHT CET 2025 (23 Apr, Shift 1) · Doppler Effect

Doppler Effect question from MHT CET 2025 (23 Apr, Shift 1)

Q12MHT CET 2025 · 23 APR · SHIFT 1Easy

Doppler Effect

An observer moves towards a stationary source of sound with a velocity of one fifth of the velocity of sound. The percentage increase in the apparent frequency is

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Answer: (c)

  1. Observer approaching: n′=nv+vovn' = n\frac{v + v_o}{v}.
  2. n′=n(1+15)=1.2nn' = n\left(1 + \frac{1}{5}\right) = 1.2n
  3. Increase =20%= 20\%. So the answer is (c) 20%20\%.
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