An observer moves towards a stationary source of sound with a velocity (1/5)th of the velocity of sound. The percentage increase in the apparent frequency is (a) 0.5% (b) 0% (c) 20% (d) 5%

Answer: (c). Observer approaching: n' = n(v + vo)/(v). n' = n(v + v/5)/(v) = 1.2n Increase = 20%. So the answer is (c) 20%.

An observer moves towards a stationary source of sound with a… | MHT CET 2026 (14 May, Shift 1)

Q4MHT CET 2026 · 14 MAY · SHIFT 1Easy

Doppler Effect

An observer moves towards a stationary source of sound with a velocity $\left(\frac{1}{5}\right)^{th}$ of the velocity of sound. The percentage increase in the apparent frequency is

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Answer: (c)

Observer approaching: $n' = n\frac{v + v_o}{v}$ .
$n' = n\frac{v + v/5}{v} = 1.2n$
Increase $= 20\%$ . So the answer is (c) $20\%$ .

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