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MHT CET 2020 (16 Oct, Shift 2) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2020 (16 Oct, Shift 2)

Q96MHT CET 2020 · 16 OCT · SHIFT 2Medium

Organ Pipes & Resonance Tube

An open organ pipe and a closed organ pipe have the frequency of their first overtone identical. The ratio of length of open pipe to that of closed pipe is

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Answer: (c)

  1. Open pipe first overtone: 2v2Lo=vLo\frac{2v}{2L_o} = \frac{v}{L_o}; closed pipe first overtone: 3v4Lc\frac{3v}{4L_c}.
  2. vLo=3v4Lc⇒Lo:Lc=4:3\frac{v}{L_o} = \frac{3v}{4L_c} \Rightarrow L_o : L_c = 4 : 3
  3. So the answer is (c) 4:34:3.
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