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MHT CET 2025 (23 Apr, Shift 2) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2025 (23 Apr, Shift 2)

Q38MHT CET 2025 · 23 APR · SHIFT 2Medium

Organ Pipes & Resonance Tube

An open organ pipe is closed such that the third overtone of the closed pipe is found to be higher in frequency by 200 Hz than the second overtone of the original pipe. The fundamental frequency of the open pipe is (Neglect end correction)

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Answer: (c)

  1. Open pipe fundamental f=v2Lf = \frac{v}{2L}; closing one end gives fundamental f2\frac{f}{2}.
  2. Closed third overtone (7th harmonic) =7f2= \frac{7f}{2}; open second overtone (3rd harmonic) =3f= 3f.
  3. 7f2−3f=f2=200⇒f=400 Hz\frac{7f}{2} - 3f = \frac{f}{2} = 200 \Rightarrow f = 400\text{ Hz}
  4. So the answer is (c) 400 Hz.
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