An organ pipe 40 cm long is open at both ends. The speed of sound in air is 360 ms⁻¹. The frequency of the second harmonic is ___________ Hz. Numerical answer type. Work it out, then open the answer.

Answer: 900. Open pipe: np=p v/2L. n₂=(2×360)/(2×0.40) n₂=900 Hz

An organ pipe 40 cm long is open at both ends. The speed of sound in… | JEE Main 2023 (8 Apr, Shift 1)

Q63JEE Main 2023 · 8 APR · SHIFT 1Easy

Organ Pipes & Resonance Tube

An organ pipe $40\text{ cm}$ long is open at both ends. The speed of sound in air is $360\text{ ms}^{-1}$ . The frequency of the second harmonic is ___________ $\text{Hz}$ .

Numerical answer type. Work it out, then open the answer.

Show answer and solution

Answer: 900

Open pipe: $n_p=\frac{p v}{2L}$ .
$n_2=\frac{2\times360}{2\times0.40}$
$n_2=900\text{ Hz}$

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