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MHT CET 2026 (15 May, Shift 2) · Organ Pipes & Resonance Tube

Organ Pipes & Resonance Tube question from MHT CET 2026 (15 May, Shift 2)

Q12MHT CET 2026 · 15 MAY · SHIFT 2Medium

Organ Pipes & Resonance Tube

An organ pipe $P_1$ closed at one end and vibrating in its first overtone and other pipe $P_2$ open at both ends vibrating in its third overtone are in resonance with a given tuning fork. The ratio of length of $P_1$ and $P_2$ will be

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Answer: (a)

Closed pipe, first overtone (3rd harmonic): $f = \frac{3v}{4L_1}$ .
Open pipe, third overtone (4th harmonic): $f = \frac{4v}{2L_2} = \frac{2v}{L_2}$ .
$\frac{3v}{4L_1} = \frac{2v}{L_2} \Rightarrow \frac{L_1}{L_2} = \frac{3}{8}$
So the answer is (a) $3 : 8$ .

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