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JEE Main 2021 (24 Feb, Shift 1) · Polarisation

Polarisation question from JEE Main 2021 (24 Feb, Shift 1)

Q46JEE Main 2021 · 24 FEB · SHIFT 1Medium

Polarisation

An unpolarised light beam is incident on the polarizer of a polarization experiment and the intensity of light beam emerging from the analyzer is measured as 100 Lumens. Now, if the analyzer is rotated around the horizontal axis (direction of light) by 30∘{}^\circ in clockwise direction, the intensity of emerging light will be _________ Lumens.

Numerical answer type. Work it out, then open the answer.

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Answer: 75

  1. Initially polarizer and analyzer are taken parallel, so the analyzer passes the full 100 lumens.
  2. Malus's law after rotating by 30∘30^\circ: I=100cos⁡230∘=100×34I = 100\cos^2 30^\circ = 100 \times \frac{3}{4}
  3. So I=75I = 75 lumens.
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