An unpolarised light of intensity 64 Wm ⁻² passes through three… | MHT CET 2026 (17 Apr, Shift 2)

Q5MHT CET 2026 · 17 APR · SHIFT 2Medium

Polarisation

An unpolarised light of intensity $64$ Wm ${}^{-2}$ passes through three polarizers successively such that the transmission axis of last polarizer is crossed with the first. The intensity of the emerging light is $6$ Wm ${}^{-2}$ . The angle between the transmission axis of the first two polarizers is

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Answer: (a)

Third polarizer crossed with the first: $I = \frac{I_0}{2}\cos^2\theta\sin^2\theta = \frac{I_0}{8}\sin^2 2\theta$
$6 = \frac{64}{8}\sin^2 2\theta \Rightarrow \sin^2 2\theta = \frac{3}{4} \Rightarrow \sin 2\theta = \frac{\sqrt{3}}{2}$
$\theta = \frac{1}{2}\sin^{-1}\left(\frac{\sqrt{3}}{2}\right)$
So the answer is (a).

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