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JEE Main 2026 (4 Apr, Shift 2) · Polarisation

Polarisation question from JEE Main 2026 (4 Apr, Shift 2)

Q8JEE Main 2026 · 4 APR · SHIFT 2Medium

Polarisation

An unpolarized light of certain intensity passes through a combination of two polarizers whose transmission axes are at 30∘30^\circ and 90∘90^\circ, respectively, with respect to the horizontal axis. A third polarizer with its transmission axis at 60∘60^\circ with the horizontal axis is placed between the two existing polarizers. The ratio of the output intensities with and without the third polarizer is ______.

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Answer: (c)

  1. Without the third: axes differ by 60∘60^\circ, I1=I02cos⁡260∘=I08I_1 = \frac{I_0}{2}\cos^2 60^\circ = \frac{I_0}{8}
  2. With the third at 60∘60^\circ: steps of 30∘30^\circ and 30∘30^\circ, I2=I02cos⁡230∘cos⁡230∘=9I032I_2 = \frac{I_0}{2}\cos^2 30^\circ\cos^2 30^\circ = \frac{9I_0}{32}
  3. I2I1=9/321/8=94\frac{I_2}{I_1} = \frac{9/32}{1/8} = \frac{9}{4}
  4. So the answer is (c) 9/4.
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