Physics Circle home Student Login

Home›Chapters›Dual Nature of Radiation and Matter PYQs›Davisson-Germer, Uncertainty, Compton & X-Rays›Question 5

JEE Main 2021 (24 Feb, Shift 2) · Davisson-Germer, Uncertainty, Compton & X-Rays

Davisson-Germer, Uncertainty, Compton & X-Rays question from JEE Main 2021 (24 Feb, Shift 2)

Q5JEE Main 2021 · 24 FEB · SHIFT 2Easy

Davisson-Germer, Uncertainty, Compton & X-Rays

An X-ray tube is operated at 1.24 million volt. The shortest wavelength of the produced photon will be:

Show answer and solution

Answer: (c)

  1. λmin=hceV\lambda_{min} = \frac{hc}{eV} with hc=1240 eV nmhc = 1240\text{ eV nm}.
  2. eV=1.24×106 eVeV = 1.24 \times 10^{6}\text{ eV}
  3. λmin=12401.24×106=10−3 nm\lambda_{min} = \frac{1240}{1.24 \times 10^{6}} = 10^{-3}\text{ nm}
  4. So the answer is (c) 10−3 nm10^{-3}\text{ nm}.
Report a mistake

More questions on Davisson-Germer, Uncertainty, Compton & X-Rays