Physics Circle home Student Login

Home›Chapters›Ray Optics PYQs›Prism, Dispersion & Scattering›Question 2

JEE Main 2026 (6 Apr, Shift 2) · Prism, Dispersion & Scattering

Prism, Dispersion & Scattering question from JEE Main 2026 (6 Apr, Shift 2)

Q2JEE Main 2026 · 6 APR · SHIFT 2Easy

Prism, Dispersion & Scattering

Angle of minimum deviation is equal to the half of the angle of prism in an equilateral prism. The refractive index of the prism is ______

Show answer and solution

Answer: (c)

  1. A=60∘A = 60^\circ, so δm=A/2=30∘\delta_m = A/2 = 30^\circ.
  2. μ=sin⁡A+δm2sin⁡A2=sin⁡45∘sin⁡30∘\mu = \dfrac{\sin\frac{A+\delta_m}{2}}{\sin\frac{A}{2}} = \dfrac{\sin 45^\circ}{\sin 30^\circ}
  3. μ=1/21/2=2\mu = \dfrac{1/\sqrt{2}}{1/2} = \sqrt{2}
  4. So the answer is (c) 2\sqrt{2}.
Report a mistake

More questions on Prism, Dispersion & Scattering