Physics Circle home Student Login

Home›Chapters›Work, Energy and Power PYQs›Work by a Variable Force›Question 10

JEE Main 2022 (26 Jun, Shift 2) · Work by a Variable Force

Work by a Variable Force question from JEE Main 2022 (26 Jun, Shift 2)

Q10JEE Main 2022 · 26 JUN · SHIFT 2Easy

Work by a Variable Force

Arrange the four graphs in descending order of total work done; where W1, W2, W3 and W4 are the work done corresponding to figure a, b, c and d respectively.

FigureFigure
FigureFigure
Show answer and solution

Answer: (a)

  1. Work = signed area under each FF-xx graph (below the axis counts negative).
  2. (a): small negative triangle (0→x0)(0 \to x_0) + positive triangle (x0→x1)(x_0 \to x_1).
  3. (b): same as (a) plus a positive rectangle (x1→x2)(x_1 \to x_2), so W2>W1W_2 > W_1.
  4. (c): same as (b) plus a positive triangle beyond x2x_2, so W3>W2W_3 > W_2.
  5. (d): a small positive part, then a large negative area up to x2x_2; net is the least, so W4W_4 is smallest.
  6. So the answer is (a) W3>W2>W1>W4W_3 > W_2 > W_1 > W_4.
Report a mistake

More questions on Work by a Variable Force