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JEE Main 2023 (15 Apr, Shift 1) · Transitions, Photon Emission & Excitation

Transitions, Photon Emission & Excitation question from JEE Main 2023 (15 Apr, Shift 1)

Q34JEE Main 2023 · 15 APR · SHIFT 1Medium

Transitions, Photon Emission & Excitation

As per given figure A,BA, B and CC are the first, second and third excited energy levels of hydrogen atom respectively. If the ratio of the two wavelengths (λ1λ2)\left(\frac{\lambda_{1}}{\lambda_{2}}\right) i.e. is 74n\frac{7}{4n}, then the value of nn will be __________.

Figure

Numerical answer type. Work it out, then open the answer.

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Answer: 5

  1. A, B, C are n=2,3,4n = 2, 3, 4. λ1\lambda_1: 3→23\to2, λ2\lambda_2: 4→34\to3.
  2. 1λ1=R(14−19)=5R36\frac{1}{\lambda_1} = R\left(\frac{1}{4} - \frac{1}{9}\right) = \frac{5R}{36}, 1λ2=R(19−116)=7R144\frac{1}{\lambda_2} = R\left(\frac{1}{9} - \frac{1}{16}\right) = \frac{7R}{144}
  3. λ1λ2=7/1445/36=720\frac{\lambda_1}{\lambda_2} = \frac{7/144}{5/36} = \frac{7}{20}
  4. 74n=720⇒n=5\frac{7}{4n} = \frac{7}{20} \Rightarrow n = 5
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