As shown in figure, a 70 kg garden roller is pushed with a force of F = 200 N at an angle of 30° with horizontal. The normal reaction on the roller is (Given g = 10 m s⁻²) (a) 800 N (b) 600 N (c) 200 √(3) N (d) 800 √(2) N

Answer: (a). The push is directed downward at 30° below the horizontal, so its vertical component presses the roller into the ground. Vertical component: Fsin 30° = 200 × 1/2 = 100 N (downward). N = mg + Fsin 30° = 700 + 100 = 800 N So the answer is (a) 800 N.

As shown in figure, a 70 kg garden roller is pushed with a force of F… | JEE Main 2023 (31 Jan, Shift 1)

Q17JEE Main 2023 · 31 JAN · SHIFT 1Easy

Connected Bodies & Pulleys

As shown in figure, a $70\text{ kg}$ garden roller is pushed with a force of $\vec{F} = 200\text{ N}$ at an angle of $30^\circ$ with horizontal. The normal reaction on the roller is

(Given $g = 10\text{ m s}^{-2}$ )

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Answer: (a)

The push is directed downward at $30^\circ$ below the horizontal, so its vertical component presses the roller into the ground.
Vertical component: $F\sin 30^\circ = 200 \times \frac{1}{2} = 100\text{ N}$ (downward).
$N = mg + F\sin 30^\circ = 700 + 100 = 800\text{ N}$
So the answer is (a) 800 N.

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