As shown in the figure, a current of 2 A flowing in an equilateral triangle of side 4√(3) cm. The magnetic field at the centroid O of the triangle is (Neglect the effect of earth's magnetic field) (a) 4√(3) × 10⁻⁴ T (b) 4√(3) × 10⁻⁵ T (c) 3√(3) × 10⁻⁵ T (d) √(3) × 10⁻⁴ T

Answer: (c). For an equilateral triangle: d = (a)/(2√(3)) = 2 cm, and each side gives (μ₀ I)/(4π d)(2sin 60°). B = 3 × 10⁻⁷ × 20.02 × √(3) B = 3√(3) × 10⁻⁵ T So the answer is (c).

As shown in the figure, a current of 2 A flowing in an equilateral… | JEE Main 2023 (30 Jan, Shift 2)

Q46JEE Main 2023 · 30 JAN · SHIFT 2Medium

Magnetic Field of Straight Wires

As shown in the figure, a current of $2\text{ A}$ flowing in an equilateral triangle of side $4\sqrt{3}\text{ cm}$ . The magnetic field at the centroid $\text{O}$ of the triangle is

(Neglect the effect of earth's magnetic field)

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Answer: (c)

For an equilateral triangle: $d = \frac{a}{2\sqrt{3}} = 2$ cm, and each side gives $\frac{\mu_0 I}{4\pi d}(2\sin 60^\circ)$ .
$B = 3 \times \frac{10^{-7} \times 2}{0.02} \times \sqrt{3}$
$B = 3\sqrt{3} \times 10^{-5}$ T
So the answer is (c).

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