As shown in the figure, a network of resistors is connected to a… | JEE Main 2023 (24 Jan, Shift 1)

Q87JEE Main 2023 · 24 JAN · SHIFT 1Medium

Kirchhoff's Laws & Measuring Instruments

As shown in the figure, a network of resistors is connected to a battery of 24V with an internal resistance of 3 $\Omega$ . The currents through the resistors R $4$ and R $5$ are I $4$ and I $5$ respectively. The values of I $4$ and I $5$ are:

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Answer: (c)

$R_1 \parallel R_2 = 1\ \Omega$ , $R_4 \parallel R_5 = \frac{20 \times 5}{25} = 4\ \Omega$
Total $R = 1 + 2 + 4 + 2 + 3 = 12\ \Omega$ , $I = \frac{24}{12} = 2\text{ A}$
Current divides inversely with resistance: $I_4 = 2 \times \frac{5}{25} = \frac{2}{5}\text{ A}$ , $I_5 = 2 \times \frac{20}{25} = \frac{8}{5}\text{ A}$
So the answer is (c).

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Kirchhoff's Laws & Measuring Instruments question from JEE Main 2023 (24 Jan, Shift 1)

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