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JEE Main 2023 (30 Jan, Shift 2) · Electric Flux & Gauss's Law

Electric Flux & Gauss's Law question from JEE Main 2023 (30 Jan, Shift 2)

Q64JEE Main 2023 · 30 JAN · SHIFT 2Easy

Electric Flux & Gauss's Law

As shown in the figure, a point charge $Q$ is placed at the centre of conducting spherical shell of inner radius $a$ and outer radius $b$ . The electric field due to charge $Q$ in three different regions $\text{I, II}$ and $\text{III}$ is given by:

$(\text{I}: r < a, \text{II}: a < r < b$ , III: $r > b$ )

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Answer: (c)

Region I ( $r < a$ ): only $Q$ is enclosed, so $E_I = \frac{kQ}{r^2} \neq 0$ .
Region II ( $a < r < b$ ): inside the conducting material, $E_{II} = 0$ (inner surface carries $-Q$ ).
Region III ( $r > b$ ): enclosed charge $= Q - Q + Q = Q$ , so $E_{III} = \frac{kQ}{r^2} \neq 0$ .
So the answer is (c).

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