As shown in the figure, after passing through the medium 1. The speed of light v₂ in medium 2 will be: ( Given c = 3 × 10⁸ ms⁻¹) (a) 1.0 × 10⁸ ms⁻¹ (b) 0.5 × 10⁸ ms⁻¹ (c) 1.5 × 10⁸ ms⁻¹ (d) 3.0 × 10⁸ ms⁻¹

Answer: (a). Refractive index n = √(μr εr). Medium 2: n₂ = √(1 × 9) = 3 (medium 1 does not affect v₂). v₂ = c/n₂ = (3 × 10⁸)/(3) = 1.0 × 10⁸ m s⁻¹. So the answer is (a).

As shown in the figure, after passing through the medium 1. The speed… | JEE Main 2022 (28 Jul, Shift 1)

Q47JEE Main 2022 · 28 JUL · SHIFT 1Medium

Refraction, Glass Slab & Apparent Depth

As shown in the figure, after passing through the medium 1. The speed of light $v_2$ in medium 2 will be:

$($ Given $c = 3 \times 10^{8}\text{ ms}^{-1}$ )

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Answer: (a)

Refractive index $n = \sqrt{\mu_r \epsilon_r}$ .
Medium 2: $n_2 = \sqrt{1 \times 9} = 3$ (medium 1 does not affect $v_2$ ).
$v_2 = \dfrac{c}{n_2} = \dfrac{3 \times 10^8}{3} = 1.0 \times 10^8\text{ m s}^{-1}$ .
So the answer is (a).

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