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NEET 2000 (AIPMT) · Rotational Kinematics & Dynamics

Rotational Kinematics & Dynamics question from NEET 2000 (AIPMT)

Q83NEET 2000 · AIPMTMedium

Rotational Kinematics & Dynamics

As shown in the figure at point O a mass is performing vertical circular motion. The average velocity of the particle is increased, then at which point will the string break

Figure

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Answer: (b)

  1. In a vertical circle T=mv2r+mgcos⁡θT = \dfrac{mv^2}{r} + mg\cos\theta (θ measured from the lowest point).
  2. At the lowest point B the speed is maximum and gravity also acts away from the centre, so tension is maximum there.
  3. So the string breaks first at B: answer (b).
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